Can anyone help me understand the following passage from the doudoroff:
Intrinsic to the function of the design (see Panning/Crossfading section below), LEFT is normalized to -5v and RIGHT is normalized to +5v.
In the diagram above this passage. “Into LEFT and out of LEFT(OUT)” appears to be a full-width LFO with survey CCW and a constant +5v when Survey is fully CW.
So if, when no attenuation is applied and LEFT to LEFT(OUT) is at full whack via cranked SURVEY, why does it appear to output +5v? I would assume by “normalled to -5v” that without any attenuation, LEFT(OUT) would simply produce a constant -5v?